π₯ PS(Problem Solving) π₯/BOJ
[BOJ] #6603 λ‘λ
dar0m!
2019. 9. 4. 00:42
μκ° μ ν | λ©λͺ¨λ¦¬ μ ν | μ λ΅ λΉμ¨ |
1 μ΄ | 128 MB | 53.637 % |
6603λ²: λ‘λ
λ¬Έμ λ μΌ λ‘λλ {1, 2, ..., 49}μμ μ 6κ°λ₯Ό κ³ λ₯Έλ€. λ‘λ λ²νΈλ₯Ό μ ννλλ° μ¬μ©λλ κ°μ₯ μ λͺ ν μ λ΅μ 49κ°μ§ μ μ€ k(k>6)κ°μ μλ₯Ό κ³¨λΌ μ§ν© Sλ₯Ό λ§λ λ€μ κ·Έ μλ§ κ°μ§κ³ λ²νΈλ₯Ό μ ννλ κ²μ΄λ€. μλ₯Ό λ€μ΄, k=8, S={1,2,3,5,8,13,21,34}μΈ κ²½μ° μ΄ μ§ν© Sμμ μλ₯Ό κ³ λ₯Ό μ μλ κ²½μ°μ μλ μ΄ 28κ°μ§μ΄λ€. ([1,2,3,5,8,13], [1,2,3,5,8,21], [1,2,3,5,8,34], [1,2
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k κ°λ‘ μ΄λ£¨μ΄μ§ μ§ν© S μμ 6κ°μ μ«μλ₯Ό μ¬μ μμΌλ‘ μΆλ ₯νλ©΄ λλ€.
λ©λͺ¨λ¦¬ | μκ° |
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#include<cstdio>
#include<algorithm>
#include<string.h>
using namespace std;
int k;
int S[15], chk[15];
void lotto(int position, int cnt) {
if (cnt >= 6) {
for (int i = 0; i < k; i++) {
if (chk[i]) {
printf("%d ", S[i]);
}
}
printf("\n");
return;
}
for (int i = position; i < k; i++) {
if (!chk[i]) {
chk[i] = 1;
lotto(i, cnt + 1);
chk[i] = 0;
}
}
return;
}
int main() {
while(1){
scanf("%d", &k);
if (k <= 0) break;
for (int i = 0; i < k; i++) {
scanf("%d", &S[i]);
}
lotto(0, 0);
memset(S, 0, sizeof(S));
memset(chk, 0, sizeof(chk));
printf("\n");
}
return 0;
}
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cs |